S000237


Pi/3 - sqrt(3)/4.

6, 1, 4, 1, 8, 4, 8, 4, 9, 3, 0, 4, 3, 7, 8, 4, 2, 2, 7, 7, 2, 3, 5, 2, 8, 7, 5, 7, 1, 6, 6, 9, 9, 5, 3, 6, 3, 3, 0, 0, 2, 1, 8, 1, 9, 6, 7, 2, 4, 4, 0, 1, 1, 6, 6, 4, 4, 3, 6, 3, 1, 1, 9, 2, 3, 9, 6, 2, 2, 2, 1, 4, 5, 3, 4, 8, 6, 9, 6, 5, 6, 9, 3, 9, 0, 5, 8, 3, 9, 5, 0, 9, 1, 3, 9, 3, 5, 4, 5, 4, 0, 8, 4, 7, 6

1

S000237

When a 30-60-90 triangle is inscibed in a unit half-circle (having diameter 2), this is the area of larger circular segment.

T. D. Noe, Plot of 1000 terms

T. D. Noe, Table of 1000 terms

Eric W. Weisstein, Circular segment

Wikipedia, Circular segment

This is Pi/n - sqrt((p^2+q^2)*((p-1)^2+q^2)), where p = (1 + cos(2*Pi/n))/2 and q = sin(2*Pi/n)/2 for n=3.

The number is 0.61418484930437842277235287571669953633002181967244….

(Mma) RealDigits[Pi/3 - Sqrt[3]/4, 10, 105][[1]]

Cf. S000236 (circular segment for square) S000238 (smaller circular segment), S000243-S000249.

nonn,cons

T. D. Noe, Sep 02 2014

© Tony D Noe 2014-2015